秀一下自己之前寫過的解決"在123456789中插入+和-使得結果為100"的程式
#include
<stdio.h>
#include
<stdlib.h>
#define C10(x) if((x)==num)printf("%s = %d\n",#x,num);
#define C9(x) C10(x##9);C10(x+9);C10(x-9);
#define C8(x) C9(x##8);C9(x+8);C9(x-8);
#define C7(x) C8(x##7);C8(x+7);C8(x-7);
#define C6(x) C7(x##6);C7(x+6);C7(x-6);
#define C5(x) C6(x##5);C6(x+5);C6(x-5);
#define C4(x) C5(x##4);C5(x+4);C5(x-4);
#define C3(x) C4(x##3);C4(x+3);C4(x-3);
#define C2(x) C3(x##2);C3(x+2);C3(x-2);
int
main
(
int
argc
,
char
**
argv
){
int
num
;
if
(
argc
==
1
)
num
=
0
;
else
num
=
atoi
(
argv
[
1
]);
C2
(
1
);
C2
(
-
1
);
return
0
;
}
結果：
123+45-67+8-9 = 100
123+4-5+67-89 = 100
123-45-67+89 = 100
123-4-5-6-7+8-9 = 100
12+3+4+5-6-7+89 = 100
12+3-4+5+67+8+9 = 100
12-3-4+5-6+7+89 = 100
1+23-4+56+7+8+9 = 100
1+23-4+5+6+78-9 = 100
1+2+34-5+67-8+9 = 100
1+2+3-4+5+6+78+9 = 100
-1+2-3+4+5+6+78+9 = 100
